Age problems are one of the most common topics in IBPS, CAT, GMAT and other banks exams.
Students waste lots of time in this question as it look very simple but
when they start solving with triditional methods, it takes a lot of
time. Today We are solving with shortcut trick. In case of any problem, please comment below.
Best way to solve Age questions is to assume fixed period with which
further conditions will be compared. For example taking 2000 as fixed
year.
Application of this rule
Example 1
Ranjeet's age after 15 years will be 5 times his age 5 years back. What is his present age ?
Solution - Let's assume right now it is year 2000
Age of Ranjeet in 1995 = x
Age of Ranjeet in 2015 = 5x
Present age of Ranjeet (in 2000) = x+5 or 5x-15
we will solve these two equation to find x.
X= 5. Then Ranjeet's present age becomes = x +5 = 10
Example 2
Karan was 4 times old as his son 8 years back and he will be 2 times old as his son after 8 years. Calculate Karan and his son's age.
Assume that currently it is year 2000.
In 1992 Karan's age = 4x, Age of Karan's son = x
In 2008 Karan's age = 2y and Age of Karan's son = y
Now we get two equations 2y - 4x = 16 and y - x = 16
By solving this equation x = 8, so Karan' son's current age = 16 years and Karan's age = 40 years.
